6.F3 Equating the first and third equations, 4 ] . 25 T . Sl Equating the second and third equations, Kshi'eld __ A __ (T,-T )= EDA T4 hshield si so so Substituting for Tso' Thus Kshield (T . _ [T4 4J· 25 ) r. 4 4] hshield Sl ho - Ts. = EO fho - Tsi Kshield T . + EO T4. hshield si si _Kshield fT4 41" 25 T4 hshield l ho - Ts~ - EO ho This equation can be solved numerically. The correct answer has the characteristics Starting with Tsi = Tho and reducing Tsi' the equation will have only one root with those characteristics satisfied. Substituting E = (.9); a= (5.74xl08 ); hshield (2.5); Tho= (295): [ 9 4]·25 -(.4) Kshield (7.57xl0) - Tsi
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