One thus obtains 7. 46 1496t 2 + 53,701 ksi 1000t2 1496t2 + 53,701 1/2 [ 1000t2 (t2) < 49. 50 1496t2 + 53,701 2 or [ l000t 2 J t 2 < 2450 Taking the limiting case where "less than" is replaced by ''equals:, we obtain: 2.2893xl0 9 ::t:. /(2.2893xl0 9 ) 2 - 4(2.238xl0 6 ) (2.8838xl0 9 ) 2(2.238xl0 6 ) t 2 = 1.26 in Thus, the minimum plate thickness necessary to ensure the fulfillment of the leak before break requirement for the outer hull is 1.26 in.or 3.20 cm. The minimum thicknesses required for the inner hull and bulkheads may be determined in a similar manner by substituting the appropriate relation between 0 8 and t into the above analysis. Clearly, the designer would use a plate thickness somewhat larger than the minimum obtained here. The decision regarding the ultimate choice of plate thickness will depend to a great extent upon the speed with which damage can be repaired as well as the maximum expected rate of damage accumulation. It will require a detailed analysis of these topics before the optimum margin of safety can be determined.
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