In order to calculate entropy generation in HW (the heat engine) the efficiency H„w is defined as: Equations 3, 4 and 21 can be combined to yield: Using equation 1 to eliminate Q' from equation 22 I derive: Landsberg and Baruch [13| did not take the rate of entropy generation SgHW into account in their analysis. These authors considered the converter I1W to be a reversible Carnot engine. In this case r)HW = 1 - a/b, and combining this with equation 23 we see that SgR" vanishes. It is now possible to draw some interesting conclusions regarding the case where the pump, sink, RI I and HW are in equilibrium. In this case the three T, are equal black body temperatures. Consequently, a=b= 1 and tjhw = 0. From equation 23 we can now calculate that Ss"w = 0 without further information. For RI I, equilibrium only obtains when SgRH = 0. Manipulating equation 20 we find that the condition must be fulfilled. If a hemispherical pump is considered, (r4 = 1) equilibrium only occurs when Pc = Pp.
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