The fact that the index k doesn’t appear on the right side of 20 shows that [] is independent of k, i.e., the beam does have a peak and it points towards O’. Dropping the subscript, and expanding sin [] gives We assumed in the foregoing that [] is fixed, but the case of time varying [] can be handled by a straightforward extension of that analysis. If we do this, (A14) becomes where []. As one would expect, only the differential phase error is affected.
RkJQdWJsaXNoZXIy MTU5NjU0Mg==