Letting [] be the angle between the Y axis and the retrodirected ray incident on the pilot source, we have from (B5) Assuming that A1? is small, where []. Solving for the pointing error, Aip, from (B6) and (B7) and dropping []) terms, we get (B6) and (B7) break down for ip in the neighborhood of +-/2 but we can still get (B8) for this case by writing (B6) and (B7) in terms of [] for ip near [], or [] for ip near []. Dropping [] ) terms is justified because [] for all existing or foreseeable spacecraft.
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